4a^2-6a-4=-5

Solution for 4a^2-6a-4=-5 equation:

4a^2-6a-4=-5

We move all terms to the left:

4a^2-6a-4-(-5)=0

We add all the numbers together, and all the variables

4a^2-6a+1=0

a = 4; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·4·1
Δ = 20
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20}=\sqrt{4*5}=\sqrt{4}*\sqrt{5}=2\sqrt{5}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{5}}{2*4}=\frac{6-2\sqrt{5}}{8}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{5}}{2*4}=\frac{6+2\sqrt{5}}{8}
$